26y^2+2y-57=0

Solution for 26y^2+2y-57=0 equation:

26y^2+2y-57=0

a = 26; b = 2; c = -57;
Δ = b2-4ac
Δ = 22-4·26·(-57)
Δ = 5932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5932}=\sqrt{4*1483}=\sqrt{4}*\sqrt{1483}=2\sqrt{1483}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1483}}{2*26}=\frac{-2-2\sqrt{1483}}{52}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1483}}{2*26}=\frac{-2+2\sqrt{1483}}{52}
$